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# Simplification Tricks for SSC

Simplification Tricks for SSC:Qualitative aptitude always starts with simplification. Simplification is a very important part in SSC, IBPS, Railway and SBI exams.  Student’s sometime neglect this topic thinking this is easy. But the main thing is Simplification is used in all types of problems from boat to SI. So if you are not given any questions from simplification directly than also you do some questions indirectly. Here we will give some question from easy based on previous year questions. The smallest possible three place decimal number is :

(1) 0.012

(2) 0.123

(3) 0.111

(4) None of the above

When 335 is added to 5A7, the result is 8B2. 8B2 is divisible
by 3. What is the largest possible value of A ?

(1) 8

(2) 2

(3) 1

(4) 4

If a number is as much greater than 31 as it is less than 75, then the number is

(1) 106

(2) 44

(3) 74

(4) 53

Which of the following numbers will always divide a six-digit number of the form xyxyxy (where 1 < x < 9, 1 < y < 9)?

(1) 1010

(2) 10101

(3) 11011

(4) 11010

The divisor is 25 times the quotient and 5 times the remainder. If the quotient is 16, the dividend is :

(1) 6400

(2) 6480

(3) 400

(4) 480

A number when divided by 899 gives a remainder 63. If the same number is divided by 29, the remainder will be :

(1) 10

(2) 5

(3) 4

(4) 2

When a number is divided by 56, the remainder obtained is 29. What will be the remainder when the number is divided by 8 ?

(1) 4

(2) 5

(3) 3

(4) 7

A six digit number is formed by repeating a three digit number; for example, 256, 256 or 678, 678 etc. Any number of this form is always exactly divisible by :

(1) 7 only

(2) 11 only

(3) 13 only

(4) 1001

A number being divided by 52 gives remainder 45. If the number is divided by 13, the remainder will be

(1) 5

(2) 6

(3) 12

(4) 7

The smallest number to be added to 1000, so that 45 divides the sum exactly, is :

(1) 35

(2) 80

(3) 20

(4) 10

The sum of first sixty numbers from one to sixty is divisible by

(1) 13

(2) 59

(3) 60

(4) 61

A number when divided by 3 leaves a remainder 1. When the quotient is divided by 2, it leaves a remainder 1. What will be the remainder when the number is divided by 6?

(1) 3

(2) 4

(3) 5

(4) 2

When a number is divided by 893, the remainder is 193. What will be the remainder when it is divided by 47 ?

(1) 3

(2) 5

(3) 25

(4) 33

A number divided by 13 leaves a remainder 1 and if the quotient, thus obtained, is divided by 5, we get a remainder of 3. What will be the remainder if the number is divided by 65 ?

(1) 28

(2) 16

(3) 18

(4) 40

A number, when divided by 119, leaves a remainder of 19. If it is divided by 17, it will leave a remainder of :

(1) 19

(2) 10

(3) 7

(4) 2

Which of the following number is NOT divisible by 18 ?

(1) 54036

(2) 50436

(3) 34056

(4) 65043

64329 is divided by a certain number. While dividing, the numbers, 175, 114 and 213 appear as three successive remainders.The divisor is

(1) 184

(2) 224

(3) 234

(4) 296

In a question on division, the divisor is 7 times the quotient and 3 times the remainder. If the remainder is 28, then the dividend is

(1) 588

(2) 784

(3) 823

(4) 1036

## More Simplification Tricks for SSC

Importance : Divisibility questions, if not asked directly, still its knowledge is very essential to solve different questions in simplification. Scope of questions : The study of this concept is very useful to increase speed in simplification and number system. Simplification Tricks for SSC.

Way to success : The knowledge of divisibility rules (of ,2, 3, 4, 5, 6, 8, 9 ) and of osculaters for 7, 11, 13 etc & mental calculations increase our (speed) time management and accuracy.

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